Here's a graph of the function: Note that it is the cosine function, but stretched in the vertical direction by the factor $2$ and “compressed” in the horizontal direction by the factor $3$.

1 Critical points are not where the function is $0.$ You want to find the points where the derivative is $0.$ Unfortunately, your function does not happen to be differentiable at $2$ or $-2,$ so you …

I thought that to find the critical points, I have to find the 1st derivative and to find local max/min or saddle, I have to use the second derivative test. I am having a little trouble both in finding first …

Usually you would define a "critical point" as the zero-points of the first derivative of your function. Since this functions first derivative has no zero-point, the critical point you search for is …

Feb 3, 2019 · 1 How do you know if a function has infinite critical points? I have learned that you can find critical points by setting the derivative of separate axes to 0 and solving, but I also …

to find the critical points of this function, you can either do f' (x) = 0 directly using the chain rule or you can note the following: Please consider the following:

Feb 24, 2021 · And since you find critical points where g' (x)=0 wouldn't that mean everywhere is a critical point? I know this can't be true but having hard time figuring out what to do.

I am having difficulties in understanding the steps/method required to find the critical points of a function using the method of Lagrange multipliers. I have read through my text book and tried …

Critical Points are Stationary points and non differentiable points. Your reasoning is correct ! The only think we need to look in these cases that the point we have found out to be critical lies in …

Setting [Math Processing Error] g (x) = 0 like I was taught in class, I am unable to find the critical points. The farthest I can get is: xeu = 2eu x e u = 2 e u where u = that annoying exponent. …