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  1. What is a Commutator? - BYJU'S

    What is a Commutator? Commutators are used in DC machines (DC motors and DC generators) universal motors. In a motor, a commutator applies an electric current to the windings. A …

  2. What is a commutator - Mathematics Stack Exchange

    The second way is to look at the commutator subgroup as a measure of how noncommutative a group is. A group is commutative if it has a trivial commutator subgroup (and highly …

  3. How to show that the commutator subgroup is a normal subgroup

    The commutator subgroup is generated by commutators. Show that the property of "being a commutator" is invariant under conjuation (in fact it is invariant under all automorphisms).

  4. Understanding the commutator subgroup of the dihedral group

    @NizarHalloun: Terminology issue: A "commutator" is an element of a group. You are talking about the "commutator subgroup," which is the subgroup generated by commutators.

  5. The commutator of two matrices - Mathematics Stack Exchange

    The commutator [X, Y] of two matrices is defined by the equation $$\begin {align} [X, Y] = XY − YX. \end {align}$$ Two anti-commuting matrices A and B satisfy $$\begin {align} A^2=I \qu...

  6. Center-commutator duality - Mathematics Stack Exchange

    So here's a sense in which the commutator subgroup and the center are "dual": the commutator is the subgroup generated by all values of $\mathbf {w} (x,y)$, and the center is the subgroup of …

  7. Why is the commutator defined differently for groups and rings?

    Jun 30, 2015 · The commutator of a group and a commutator of a ring, though similar, are fundamentally different, as you say. In each case, however, the commutator measures the …

  8. Commutator Group of $\\operatorname{GL}_2(\\mathbb{R})$ is ...

    May 2, 2018 · Let $\operatorname {GL}_2 (\mathbb {R})$ be the general linear group of $2\times2$ matrices and $\operatorname {SL}_2 (\mathbb {R})$ the special linear group of $2 …

  9. Commutator of $p^2$ and $x$ - Mathematics Stack Exchange

    Jan 23, 2020 · Writing in more details, the commutator relation is $$ [p,x]=-i\hbar I$$ where $I$ is the identity operator. So $pi\hbar$ should be understood as $pi\hbar I$, the composition of the …

  10. Calculating the commutator (derived) subgroup of $S_3$

    If $x$ and $y$ are in $S_3$, then their commutator, $x^ {-1}y^ {-1}xy$, is an even permutation. So the commutator subgroup is a subgroup of $A_3$, which is just the identity and the 3-cycles.